question_answer

The magnitude of the magnetic field at the center of an equilateral triangular loop of side 1m which is carrying a current of 10 A is : \[[\text{Take}\,{{\mu }_{0}}=4\pi \times {{10}^{-7}}N{{A}^{-2}}]\] [JEE Main 10-4-2019 Afternoon]

A) \[18\mu T\]

B) \[3\mu T\]

C) \[1\mu T\]

D) \[9\mu T\]

Correct Answer: A

Solution :

[a]

Here,