A) \[T=\sqrt{\frac{2\pi m}{IB}}\]
B) \[T=\sqrt{\frac{\pi m}{IB}}\]
C) \[T=\sqrt{\frac{2m}{IB}}\]
D) \[T=\sqrt{\frac{\pi m}{2IB}}\]
Correct Answer: A
Solution :
[a] \[\tau =MB\sin \theta =I\alpha \] |
\[\pi {{R}^{2}}IB\theta =\frac{M{{R}^{2}}}{2}\alpha \] |
\[\omega =\sqrt{\frac{2\pi IB}{m}}\] |
\[T=\sqrt{\frac{2\pi M}{IB}}\] |
You need to login to perform this action.
You will be redirected in
3 sec