A) \[-2F\]
B) \[F/3\]
C) \[-2F/3\]
D) \[-F/3\]
Correct Answer: C
Solution :
| [c] Force acting between two current carrying m conductors |
| \[F=\frac{{{\mu }_{0}}}{2\pi }\frac{{{l}_{1}}{{l}_{2}}}{d}I\] ..(i) |
| where, \[d=\]distance between the conductors |
| \[l=\]length of each conductor |
| Again, \[F'=\frac{{{\mu }_{0}}}{2\pi }\frac{(-2{{l}_{1}})({{l}_{2}})}{(3d)}l\] |
| \[F'=\frac{{{\mu }_{0}}}{2\pi }\frac{(-2{{l}_{1}})({{l}_{2}})}{(3d)}l\] .(ii) |
| Thus, from Eqs. (i) and (ii), we get |
| \[\frac{F'}{F}=-\frac{2}{3}\] |
| \[\Rightarrow \] \[F'=-\frac{2}{3}F\] |
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