JEE Main & Advanced Physics Mathematical Tools, Units & Dimensions JEE PYQ - Mathematical Tools Units and Dimensions

  • question_answer
    Given that K = energy, V= velocity, T= time. If they are chosen as the fundamental units, then what is dimensional formula for surface tension?                        [JEE ONLINE 07-05-2012]

    A) \[[K{{V}^{-2}}{{T}^{-2}}]\]

    B) \[[{{K}^{2}}{{V}^{2}}{{T}^{-2}}]\]

    C) \[[{{K}^{2}}{{V}^{-2}}{{T}^{-2}}]\]

    D) \[[K{{V}^{2}}{{T}^{2}}]\]

    Correct Answer: A

    Solution :

    [a] Surface tension,\[T=\frac{F}{\ell }=\frac{F}{\ell }.\frac{\ell }{\ell }.\frac{{{T}^{2}}}{{{T}^{2}}}\]
    (As,\[F.\ell =K\](energy)\[\frac{{{T}^{2}}}{{{\ell }^{2}}}={{V}^{-2}}\])
    Therefore, surface tension\[=[K{{V}^{-2}}{{T}^{-2}}]\]


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