A) \[[{{M}^{-2}}{{L}^{-2}}{{T}^{6}}{{A}^{3}}]\]
B) \[[{{M}^{-1}}{{L}^{-2}}{{T}^{4}}{{A}^{2}}]\]
C) \[[{{M}^{-3}}{{L}^{-2}}{{T}^{8}}{{A}^{4}}]\]
D) \[[{{M}^{-2}}{{L}^{0}}{{T}^{-4}}{{A}^{-2}}]\]
Correct Answer: C
Solution :
[c] \[X=5Y{{Z}^{2}}\] |
\[Y=\frac{X}{5{{Z}^{2}}}\] |
\[[Y]=\frac{[X]}{[{{Z}^{2}}]}\] |
\[=\frac{{{A}^{2}}.{{M}^{-1}}{{L}^{-2}}.{{T}^{4}}}{{{(M{{A}^{-1}}{{T}^{-2}})}^{2}}}\] |
\[={{M}^{-3}}.\,{{L}^{-2}}.\,{{T}^{8}}.\,{{A}^{4}}\] |
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