A) 0.5 mA
B) 0.05 mA
C) 0.2 mA
D) 0.02 mA
Correct Answer: C
Solution :
[c] \[I=\left( {{e}^{\frac{^{1000V}}{T}}}-1 \right)\] |
\[\frac{dI}{dV}=\frac{1000}{T}{{e}^{\frac{1000V}{T}}}\] |
\[dI=\left( \frac{1000}{T}{{e}^{\frac{1000V}{T}}} \right)dV\] \[I=5MA\] |
\[\Rightarrow \]\[e\frac{1000V}{T}=6MA\] |
\[dI=\left( \frac{1000}{300} \right)(0.01)(6)=\frac{10}{50}=\frac{1}{5}\] |
\[dI=0.2mA\] |
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