A) 92 ± 3 s
B) 92 ± 2 s
C) 92 ± 5.0 s
D) 92 ± 1.8 s
Correct Answer: B
Solution :
[b] \[{{T}_{AV}}=92s\] |
\[{{(|\Delta T|)}_{mean}}=1.5s\]since uncertainity is 1.5 s |
so digit 2 in 92 is uncertain. |
so reported mean time should be 92 ± 2 |
Ref: NCERT (XIth) Ex. 2.7, Page. 25 |
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