A) Energy
B) Area
C) Volume
D) Momentum
Correct Answer: A
Solution :
| [a] \[\frac{hc}{\lambda }=E\Rightarrow \left[ hc \right]=\left[ M{{L}^{2}}{{T}^{-2}} \right]\left[ L \right]=\left[ M{{L}^{3}}{{T}^{-2}} \right]\] |
| \[[c]=[L{{T}^{-1}}]\] |
| \[[G]=[{{M}^{-1}}{{L}^{3}}{{T}^{-2}}]\] \[\left\{ \begin{matrix} F=\frac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}} \\ \Rightarrow G=\frac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}} \\ \end{matrix} \right.\] |
| \[\Rightarrow \,\,\,\,\left[ \sqrt{\frac{h{{c}^{5}}}{G}} \right]=\left[ M{{L}^{2}}{{T}^{-2}} \right]=\]Energy |
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