JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    A block of mass M is pulled along a horizontal frictionless surface by a rope of mass m. If a force P is applied at the free end of the rope, the force exerted by the rope on the block is [AIEEE 2003]

    A) \[\frac{P\,m}{M+m}\]

    B) \[\frac{P\,m}{M-m}\]

    C)             P

    D) \[\frac{P\,M}{M+m}\]

    Correct Answer: D

    Solution :

    [d] Let acceleration of system (rope + block) is a along the direction of applied force. Then,
                            \[a=\frac{P}{M+m}\]                ….. (i)
    Frictionless surface
    Draw the FBD of block and rope as shown in figure below.
    where, T is the required parameter (i.e., force)
    For block       T = Ma
                \[\Rightarrow \]   \[T=\frac{MP}{M+m}\] [from Eq. (i)]

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