JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    A body A of mass M while falling vertically downwards under gravity breaks into two parts; a body B of mass\[\frac{1}{3}\]M and a body C of mass\[\frac{2}{3}\]M. The centre of mass of bodies B and C taken together shifts compared to that of body A towards                        [AIEEE 2005]

    A) depends on height of breaking

    B) does not shift

    C) body C

    D) body B

    Correct Answer: B

    Solution :

    [b] Since, the acceleration of centre of mass in both the cases is same equal to g. So, the centre of mass of the bodies B and C taken together does not shift compared to that of body A.

You need to login to perform this action.
You will be redirected in 3 sec spinner