Three forces start acting C simultaneously on a particle moving with velocity v. These forces are represented in magnitude and direction by the three sides of a \[\Delta ABC\] (as shown). The particle will now move with velocity |
[AIEEE 2003] |
A) less than v
B) greater than v
C) \[\left| v \right|\] in the direction of largest force BC
D) v remain unchanged
Correct Answer: D
Solution :
[d] Resultant force is zero, as three forces acting on the particle can be represented in magnitude and direction by three sides of a triangle in same order. Hence, by Newton's 2nd law \[\left( F=m\frac{d\,\,v}{dt} \right)\], particle velocity (v) will be same. (\[\because \] if F = 0, v = constant) |
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