A) g, g
B) g-a, g-a
C) g-a, g
D) a, g
Correct Answer: C
Solution :
[c] The net force in any direction equal the product of mass and acceleration in the direction of net force. Also net force means the vector sum of forces acting on a body. |
Apparent weight of ball |
\[w'=w-R\] |
\[R=ma\] (acts upward) |
\[mg-R=ma\] |
\[w'=mg-ma=m(g-a)\] |
Hence, apparent acceleration in the lift is g a. Now, if the man is standing stationary on the ground, then the apparent acceleration of the falling ball is g. |
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