Three identical blocks of masses \[m=2\] kg are drawn by a force \[F=10.2\] N with an acceleration of \[0.6\,\,m{{s}^{-2}}\] on a frictionless surface, then what is the tension (in N) in the string between the blocks B and C? [AIEEE 2002] |
A) \[9.2\]
B) \[7.8\]
C) 4
D) \[9.8\]
Correct Answer: B
Solution :
[b] The system of masses is shown below. |
From the figure. |
For block A, \[F-{{T}_{1}}=\] ma ... (i) |
and for block B, \[{{T}_{1}}-{{T}_{2}}=\] ma ... (ii) |
Eq. (i) gives |
\[102-{{T}_{1}}=2kt-0.6\Rightarrow {{T}_{1}}=102-12=9\,N\] |
Again from Eq. (ii), we get |
\[9-{{T}_{2}}=2\times 0.6\] |
\[\Rightarrow \] \[{{T}_{2}}=9-1.2=7.8\,N\] |
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