A) 2.0
B) 4.0
C) 1.6
D) 2.5
Correct Answer: A
Solution :
[a] For a body or system to be in equilibrium net force acting on the body or system should be, zero. i.e., sum of component of all the forces acting in a particular direction is zero. |
Let the mass of block be m. |
Frictional force in rest position |
\[F=mg\text{ }\sin \text{ }30{}^\circ \] |
(this is static frictional force and may be less than the limiting frictional force) |
At the condition of equilibrium block on incline. |
\[10=m\times 10\times \frac{1}{2}\] |
\[\therefore \] \[m=\frac{2\times 10}{10}=2\,kg\] |
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