A block is kept on a frictionless inclined surface with angle of inclination a. The incline is given an acceleration a to keep the block stationary. Then, a is equal to [AIEEE 2005] |
A) \[g/tan\alpha \]
B) \[g\text{ }\cos ec\alpha \]
C) \[g\]
D) \[g\text{ }tan\alpha \]
Correct Answer: D
Solution :
[d] If there is not a direct force on a body except contact force, then we must assume a pseudo force on the body in a direction opposite to the actual force and after that we conclude all the forces acting on the body. |
In the frame of wedge, the force diagram of block is shown in figure. From free body diagram of wedge, |
For block to remain stationary, |
(along incline) |
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