A uniform sphere of weight W and radius 5cm is being held by a string as shown in the figure. The tension in the string will be: [JEE ONLINE 09-04-2013] |
A) \[12\frac{W}{5}\]
B) \[5\frac{W}{12}\]
C) \[13\frac{W}{12}\]
D) \[13\frac{W}{12}\]
Correct Answer: D
Solution :
[d] |
\[T\cos \theta =w\] |
\[T=\frac{w}{\cos \theta }\] |
\[\cos \theta =\frac{AB}{AC}=\frac{AB}{AD+BC}=\frac{AB}{8+5}=\frac{AB}{13}\] |
From right angle triangle \[AB=12\] |
So \[T=\frac{w\times 13}{12}\] |
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