JEE Main & Advanced Physics NLM, Friction, Circular Motion JEE PYQ - NLM Friction Circular Motion

  • question_answer
    An L-shaped object, made of thin rods of uniform mass density, is suspended with a string as shown in figure. If \[\,AB=BC\], and the angle made by AB with downward vertical is \[\theta \], then: [JEE Main 09-Jan-2019 Morning]

    A)             \[\tan \,\theta \,\,=\,\,\frac{1}{3}\]

    B) \[\tan \,\theta \,\,=\,\,\frac{1}{2}\]

    C)             \[\tan \,\theta \,\,=\,\,\frac{2}{\sqrt{3}}\]

    D) \[\tan \,\theta \,\,=\,\,\frac{1}{2\sqrt{3}}\]

    Correct Answer: A

    Solution :

    [a]
               
                \[mg\text{ }\frac{a}{2}\,{{d}_{1}}=\,\,mg{{d}_{2}}\]
                \[mg\frac{a}{2}\,\sin \,\theta \,\,\,=\,\,\,mg\,(\frac{a}{2}\,\cos \,\theta \,\,-\,\,a\sin \,\theta )\]
                \[\frac{\sin \,\theta }{2}\,\,=\,\,\frac{\cos \,\theta }{2}\,\,-\,\sin \,\theta \]
                \[\frac{3}{2}\,\sin \,\theta \,\,=\,\,\frac{\cos \,\theta }{2}\]
                \[\tan \,\theta \,\,=\,\,\frac{1}{3}\]


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