A block of mass 5 kg is (i) pushed in case and (ii) pulled in case , by a force F = 20 N, making an angle of \[30{}^\text{o}\] with the horizontal, as shown in the figures. The coefficient of friction between the block and floor is \[\mu =0.2.\]The difference between the accelerations of the block, in case and case will be : \[(g=10m{{s}^{-2}})\] |
[JEE Main 12-4-2019 Afternoon] |
A) \[0m{{s}^{-2}}\]
B) \[0.8\,m{{s}^{-2}}\]
C) \[0.4\,m{{s}^{-2}}\]
D) \[3.2\,m{{s}^{-2}}\]
Correct Answer: B
Solution :
[b] |
\[{{N}_{1}}=60\] \[{{N}_{2}}=40\] |
\[{{a}_{1}}=\frac{10\sqrt{3}-0.2\times 60}{5}\] \[{{a}_{2}}=\frac{10\sqrt{3}-0.2\times 40}{5}\] |
\[{{a}_{1}}-{{a}_{2}}=0.8\] |
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