• # question_answer A mass of 10 kg is suspended by a rope of length 4 m, from the ceiling. A force F is applied horizontally at the mid-point of the rope such that the top half of the rope makes an angle of $45{}^\circ$ with the vertical. Then F equals: (Take $g=10\text{ }m{{s}^{2}}$ and the rope to be massless) [JEE MAIN Held on 07-01-2020 Evening] A) 75 N     B) 70 N C) 90 N     D) 100 N

 [d] ${{T}_{2}}\text{ }cos\,45{}^\circ =100\text{ }N$                       ...(i) ${{T}_{2}}\text{ }sin\,45{}^\circ =F$                          ...(ii) $\Rightarrow \,\,F=100\text{ }N$