A) 1 cm
B) 2cm
C) 3 cm
D) 4 cm
Correct Answer: A
Solution :
[a] Let initial velocity of body at point A be v, AB is 3 cm. |
From \[{{v}^{2}}={{u}^{2}}-2\]as |
\[{{\left( \frac{v}{2} \right)}^{2}}={{v}^{2}}-2a\times 3\] |
Let after penetrating 3 cm in a wooden block, the body moves x distance from B to C and comes to rest. |
So, for B to C |
\[u=\frac{v}{2},\,\,v=0\], |
\[s=x,\,a=\frac{{{v}^{2}}}{8}\] (retardation) |
\[\therefore \] \[{{(0)}^{2}}={{\left( \frac{V}{2} \right)}^{2}}-2.\frac{{{V}^{2}}}{8}.\,x\] |
\[x=1\,cm\] |
NOTE: Here, it is assumed that retardation is uniform. |
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