A) \[_{6}^{12}C\]
B) \[_{5}^{10}B\]
C) \[_{5}^{9}B\]
D) \[_{4}^{11}Be\]
Correct Answer: B
Solution :
[b] As ![]() |
it implies that ![]() |
and ![]() |
Thus, it is boron ![]() |
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