A) \[\left( -\hat{i}-3\hat{j}+2\hat{k} \right)\]
B) \[\left( +\hat{i}-3\hat{j}-2\hat{k} \right)\]
C) \[\left( -\hat{i}+3\hat{j}-2\hat{k} \right)\]
D) \[\left( +\hat{i}+3\hat{j}-2\hat{k} \right)\]
Correct Answer: D
Solution :
[d] \[\hat{E}=-\hat{p}\] |
\[\Rightarrow \hat{E}=-\left[ \frac{-\hat{i}-3\hat{j}+2\hat{k}}{\sqrt{14}} \right]\] |
\[\left| {\vec{E}} \right|=\frac{k\left| {\vec{p}} \right|}{{{r}^{3}}}\] |
\[\hat{E}\] is parallel to \[\left( \hat{i}+3\hat{j}-2\hat{k} \right)\] |
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