A) \[{{\lambda }_{B}}={{\lambda }_{G/3}}\]
B) \[{{\lambda }_{B}}={{\lambda }_{G/2}}\]
C) \[{{\lambda }_{B}}=2{{\lambda }_{G}}\]
D) \[{{\lambda }_{B}}=3{{\lambda }_{G}}\]
Correct Answer: D
Solution :
| [d] de-Broglie wavelength |
| \[\lambda =\frac{h}{mv}\] |
| \[mvr=\frac{nh}{2\pi }\] |
| \[\frac{h}{mv}=\frac{2\pi r}{n}\] |
| \[\lambda =\frac{2\pi r}{n}\] |
| \[r={{a}_{0}}\frac{{{n}^{2}}}{Z}\] |
| \[\lambda =\frac{2\pi {{a}_{0}}n}{Z}\] |
| As the atom is hydrogen Z = 1 |
| \[{{\lambda }_{B}}=\frac{2\pi {{a}_{0}}3}{Z}\] |
| \[{{\lambda }_{G}}=\frac{2\pi a0}{Z}\] |
| \[{{\lambda }_{B}}=3{{\lambda }_{G}}\] |
You need to login to perform this action.
You will be redirected in
3 sec
