A) real and at a distance of 40 cm from the divergent lens
B) real and at a distance of 6 cm from the convergent lens
C) real and at a distance of 40 cm from convergent lens
D) virtual and at a distance of 40 cm from convergent lens.
Correct Answer: C
Solution :
[c] As parallel beam incident on diverging lens if forms virtual image at \[{{v}_{1}}=-25\,cm\]from the diverging lense which works as a object for the converging lense (f = 20 cm) |
So for converging lens |
Finance image |
V = 40 cm from converging lenses. |
You need to login to perform this action.
You will be redirected in
3 sec