question_answer

A diverging lens with magnitude of focal length 25 cm is placed at a distance of 15 cm from a converging lens of magnitude of focal length 20 cm. A beam of parallel light falls on the diverging lens. The final image formed is: [JEE Main 2017]

A) real and at a distance of 40 cm from the divergent lens

B) real and at a distance of 6 cm from the convergent lens

C) real and at a distance of 40 cm from convergent lens

D) virtual and at a distance of 40 cm from convergent lens.                   

Correct Answer: C

Solution :

[c] As parallel beam incident on diverging lens if forms virtual image at \[{{v}_{1}}=-25\,cm\]from the diverging lense which works as a object for the converging lense (f = 20 cm)

So for converging lens

Finance image

V = 40 cm from converging lenses.