A) \[6.25\times {{10}^{4}}J\]
B) \[1.13\times {{10}^{3}}J\]
C) \[8.75\times {{10}^{\,4}}\text{ }J\]
D) \[8.75\times {{10}^{3}}\text{ }J\]
Correct Answer: C
Solution :
[c] |
\[KE\,\,=\,\,\frac{1}{2}\,\,\left( \frac{2}{5}\,\,m{{R}^{2}}\,\,+\,\,m{{R}^{2}} \right)\,\,{{\left( \frac{v}{R} \right)}^{2}}\] |
\[\Rightarrow \,\,KE\,\,=\,\,\frac{1}{2}\,m{{R}^{2}}\,\,\times \,\,\frac{7}{5}\,\,\times \,\,\frac{{{v}^{2}}}{{{R}^{2}}}\,\,=\,\,\frac{7}{10}\,\,\times \,\,\frac{1}{2}\,\,\times \,\,\frac{25}{{{10}^{4}}}\] |
\[KE\,\,=\,\,\frac{35}{4}\,\,\times \,\,{{10}^{-\,4}}\,\,Joule\] |
\[KE\,\,=\,\,8.75\,\,\times \,\,{{10}^{\,4}}\,\,Joule\] |
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