As shown in fig. when a spherical cavity (centred at O) of radius 1 is cut out of a uniform sphere of radius R (centred at C), the centre of mass of remaining (shaded) part of sphere is at G, i.e. on the surface of the cavity. R can be determined by the equation [JEE MAIN Held on 08-01-2020 Evening] |
A) \[\left( {{R}^{2}}\text{+}R+1 \right)\left( 2R \right)=1\]
B)
C)
D)
Correct Answer: A
Solution :
[a] \[{{M}_{0}}=\frac{4}{3}\pi {{R}^{3}}\rho \] xYou need to login to perform this action.
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