question_answer

A 70 Kg man leaps vertically into the air from a crouching position. To take the leap the man pushes the pushes the ground with a constant force F to raise himself. The center of gravity rises by 0.5 m before he leaps. After the leap the c.g. rises by another 1 m. The maximum power delivered by the muscles is: (Take g = 10 \[\text{m}{{\text{s}}^{\text{2}}}\]).                                                                                                                                    [JEE ONLINE 23-04-2013]

A)         \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{3}}}\] Watts at the start

B)   \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{3}}}\] Watts at take off

C)        \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{4}}}\] Watts at the start

D)   \[\text{6}\text{.26}\times \text{1}{{\text{0}}^{\text{4}}}\] Watts at take off