question_answer

From a solid sphere of mass M and radius R a cube of maximum possible volume is cut. Moment of inertia of cube about an axis passing through its center and perpendicular to one of its faces is:                        [JEE MAIN 2015]

A)   \[\frac{4M{{R}^{2}}}{9\sqrt{3\pi }}\]

B)        \[\frac{4M{{R}^{2}}}{3\sqrt{3\pi }}\]

C)   \[\frac{M{{R}^{2}}}{32\sqrt{2\pi }}\]

D)        \[\frac{M{{R}^{2}}}{16\sqrt{2\pi }}\]

Correct Answer: A

Solution :

[a]