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JEE Main & Advanced Physics Rotational Motion JEE PYQ-Rotational Motion

  • question_answer
    A stationary horizontal disc is free to rotate about its axis. When a torque is applied on it, its kinetic energy as a function of \[\theta ,\]where \[\theta \] is the angle by which it has rotated, is given as \[k{{\theta }^{2}}.\]If its moment of inertia is I then the angular acceleration of the disc is :                                                       [JEE Main 9-4-2019 Morning]

    A)  \[\frac{k}{2I}\theta \]                

    B)       \[\frac{k}{I}\theta \]

    C)  \[\frac{k}{4I}\theta \]                

    D)       \[\frac{2k}{I}\theta \]

    Correct Answer: D

    Solution :

    [d] Kinetic energy
                                     …(1)
    Differentiate (1) wrt time
    Option [d]


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