| Truth table for the given circuit will be [JEE Online 15-04-2018 (II)] |
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A)
B)
C)
D)
Correct Answer: C
Solution :
[c]| \[x\] | \[y\] | \[\overline{x}\] | \[a=x.y\] | \[b=\overline{x}.y\] | \[z=\overline{a.b}\] |
| 0 | 0 | 1 | 0 | 0 | 1 |
| 0 | 1 | 1 | 0 | 1 | 1 |
| 1 | 0 | 0 | 0 | 0 | 1 |
| 1 | 1 | 0 | 1 | 0 | 1 |
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