A) \[\frac{2\pi }{\alpha }\]
B) \[\frac{2\pi }{\sqrt{\alpha }}\]
C) \[2\pi \alpha \]
D) \[2\pi \sqrt{\alpha }\]
Correct Answer: B
Solution :
[b] Given, simple harmonic is |
..(i) |
We know acceleration, (ii) |
From Eqs. (i) and (ii), we have |
Or |
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