question_answer

The function\[\sin (\omega t)\]represents                                                                 [AIEEE 2005]

A)  a periodic, but not simple harmonic motion with a period \[2\pi /\omega \]

B)  a periodic, but not simple harmonic motion with a period \[\pi /\omega \]

C)  a simple harmonic motion with a period \[2\pi /\omega \]

D)  a simple harmonic motion with a period \[\pi /\omega \]

Correct Answer: B

Solution :

[b] Here,

For

Hence, function is not SHM, but periodic.

From the y-t graph, time period is.