question_answer

Two simple harmonic motions are represented    by    the    equations \[{{y}_{1}}=0.1\sin \left( 100\pi t+\frac{\pi }{3} \right)\]and\[{{y}_{2}}=0.1\,\cos \pi t.\] The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is                          [AIEEE 2005]

A)  \[\frac{-\pi }{6}\]            

B)     \[\frac{\pi }{3}\]

C)  \[\frac{-\pi }{3}\]              

D)       \[\frac{\pi }{6}\]

Correct Answer: A

Solution :

[a] Given,

or

or

and

Hence, phase difference