Two bodies of masses 1 kg and 4 kg are connected to a vertical spring, as shown in the figure. The smaller mass executes simple harmonic motion of angular frequency 25rad/s, and amplitude 1.6 cm while the bigger mass remains stationary on the ground. The maximum force exerted by the system on the floor is (take \[g=10m{{s}^{-2}}\]) [JEE ONLINE 09-04-2014] |
A) 20 N
B) 10 N
C) 60 N
D) 40 N
Correct Answer: C
Solution :
[c] Mass of bigger body M = 4 kg |
Mass of smaller body m = 1 kg |
Smaller mass (m = 1 kg) executes S.H.M of angular frequency rad/s |
Amplitude |
As we know,or |
or |
or |
The maximum force exerted by the system on the floor |
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