Two particles are performing simple harmonic motion in a straight line about the same equilibrium point. |
The amplitude and time period for both particles are same and equal to A and T, respectively. At time t = 0 one particle has displacement A while the other one has displacement \[\frac{-A}{2}\]and they are moving towards each other .If they cross each at time t, then t is: [JEE ONLINE 09-04-2016] |
A) \[\frac{T}{4}\]
B) \[\frac{5T}{6}\]
C) \[\frac{T}{3}\]
D) \[\frac{T}{6}\]
Correct Answer: D
Solution :
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