question_answer

A particle of mass m executes simple harmonic motion with amplitude a and frequency v. The average kinetic energy during its motion from the position of equilibrium to the end is                                                            [AIEEE 2007]

A)  \[p=\frac{{{E}_{0}}{{I}_{0}}}{2}\]

B)       \[P=\sqrt{2}{{E}_{0}}{{I}_{0}}\]

C)  \[{{10}^{-3}}\mu C\]      

D)       \[(\sqrt{2},\sqrt{2})\]

Correct Answer: A

Solution :

[a] The average kinetic energy of particle