A) \[2.2\,\,N/m\]
B) \[5.5\,\,N/m\]
C) \[6.4\,\,N/m\]
D) \[7.1\,\,N/m\]
Correct Answer: D
Solution :
[d] \[kx=m{{\omega }^{2}}X\] |
\[\Rightarrow k=m{{\omega }^{2}}\] |
\[=\frac{108}{6.02\times {{10}^{23}}}\times {{(2\pi \times {{10}^{12}})}^{2}}\times {{10}^{-3}}\] |
\[k\approx 7.1N/m\] |
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