question_answer

A body is in simple harmonic motion with time period half second (T = 0.5 s) and amplitude one cm (A = 1 cm). Find the average velocity in the interval in which it moves form equilibrium position to half of its amplitude.              [JEE ONLINE 19-04-2014]

A)  4 cm/s

B)       6 cm/s

C)  12 cm/s

D)      16 cm/s

Correct Answer: C

Solution :

[c] Given: Time period, T = 0.5 sec

Amplitude, A = 1 cm

Average velocity in the interval in which body moves from equilibrium to half of its amplitude, v = ?

Time taken to a displacement A/2 where A is the amplitude of oscillation from the mean position ‘O’ is

Therefore, time,

Displacement,

Average velocity,