A) 2 s
B) 5 s
C) 7 s
D) 3.5 s
Correct Answer: D
Solution :
| [d] \[E'=\frac{1}{2}\]\[b=\frac{\lambda }{m}\] \[A={{A}_{0}}{{e}^{-bt}}\] |
| \[a'=\frac{a}{\sqrt{2}}\] \[\lambda =bm\] \[\frac{1}{\sqrt{2}}\,={{e}^{-\frac{t}{10}}}\] |
| \[b=\frac{1}{10}\,\sqrt{2}\,={{e}^{\frac{1}{10}}}\] |
| \[\ln \,\sqrt{2}\,=\frac{t}{20}\] |
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