JEE Main & Advanced Physics Simple Harmonic Motion JEE PYQ-Simple Harmonic Motion

  • question_answer
    The displacement of a particle varies according to the relation\[x=4\,(\cos \pi \,t+\sin \pi t)\]. The amplitude of the particle is          [AIEEE 2003]

    A)  \[-4\]               

    B)       4

    C)  \[4\sqrt{2}\]     

    D)       8

    Correct Answer: C

    Solution :

    [c] Displacement of the particle is given as
               
    So, amplitude


You need to login to perform this action.
You will be redirected in 3 sec spinner