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JEE Main & Advanced Physics Thermodynamical Processes JEE PYQ-Thermodynamical Processes

  • question_answer
    The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process, the temperature of the gas increases   by\[7{}^\circ C\].   The   gas   is \[(R=8.3\,J\,mo{{l}^{-1}}{{K}^{-1}})\]                   [AIEEE 2006]

    A)  Diatomic

    B)  triatomic

    C)  a mixture of monatomic and diatomic

    D)  monatomic

    Correct Answer: A

    Solution :

    [a] For adiabatic process,
    So, (from 1st law,)
    (where,is degree of freedom)
    So, it is a diatomic gas.


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