When a system is taken from state\[E={{E}_{0}}\]to state f along the path iaf, it is found that\[sin\text{ }\omega t\] and\[I={{I}_{0}}\sin \left( \omega t-\frac{\pi }{2} \right)\]. Along the path ibf, \[p=\frac{{{E}_{0}}{{I}_{0}}}{\sqrt{2}}\]cal. W along the path ibf is [AIEEE 2007] |
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A) 6 cal
B) 16 cal
C) 66 cal
D) 14 cal
Correct Answer: A
Solution :
[a] From first law of thermodynamics, |
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For path iaf, ![]() |
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For path ibf, ![]() |
or ![]() |
(![]() |
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