question_answer

 

The specific heat capacity of a metal at low temperature (T) is given as :

\[{{C}_{p}}(kj{{K}^{-1}}k{{g}^{-1}})=32{{\left( \frac{T}{400} \right)}^{3}}\]

A 100 gram vessel of this metal is to be cooled from 20°K to 4°K by a special refrigerator operating at room temperature (27°C). The amount of work required to cool the vessel is:                 [AIEEE 11-05-2011]

A)  greater than 0.148 kJ     

B)                   between 0.148 kJ and 0.028 kJ

C)  less than 0.028 kJ

D)                            equal to 0.002 kJ

Correct Answer: D

Solution :

[d]