JEE Main & Advanced Physics Thermodynamical Processes JEE PYQ-Thermodynamical Processes

  • question_answer
    One mode of an ideal monoatomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, \[27{}^\circ C\]. The work done on the gas will be:                                    [JEE Online 15-04-2018]

    A)  \[300R\,\,In\,\,6\]          

    B)       \[300R\]

    C)  \[300R\,\,In\,\,7\]          

    D)       \[300R\,\,In\,\,2\]

    Correct Answer: D

    Solution :

    [d] Work done in isothermal process is given as
    \[W=-nRT\,\,In\frac{V2}{{{V}_{1}}}\]
    \[W=R\times 300In\frac{{{P}_{1}}}{{{P}_{2}}}\]
    \[W=-R\times 300In\frac{P}{2P}\]
    \[W=300R\,\,In\,\,2\]


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