A) 130 g
B) 35 g
C) 20 g
D) 150 g
Correct Answer: C
Solution :
[c] Suppose 'm' gram of water evaporates then, heat required |
\[\Delta {{Q}_{req}}=m{{L}_{\text{v}}}\] |
Mass that converts into ice = (150 - m) |
So, heat released in this process |
\[\Delta {{Q}_{rel}}=(150-m){{L}_{f}}\] |
Now, |
\[\Delta {{Q}_{rel}}=\Delta {{Q}_{req}}\] |
\[(150-m){{L}_{f}}=m{{L}_{V}}\] |
\[m({{L}_{f}}+{{L}_{\text{v}}})=150{{L}_{f}}\] |
\[m=\frac{150{{L}_{f}}}{{{L}_{f}}+{{L}_{\text{v}}}}\] |
\[m=20g\] |
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