JEE Main & Advanced Physics Transmission of Heat JEE PYQ-Transmission Of Heat

  • question_answer
    A hot body, obeying Newton’s law of cooling is cooling down from its peak value 80°C to an ambient temperature of 30°C. It takes 5 minutes in cooling down from 80°C to 40°C.                                  [JEE ONLINE 11-04-2014]
    How much time will it take to cool down from 62°C to 32°C?
    (Given In 2 = 0.693, In 5 = 1.609)

    A)  3.75 minutes

    B)       8.6 minutes

    C)  9.6 minutes      

    D)       6.5 minutes

    Correct Answer: B

    Solution :

    [b] From Newton’s law of cooling,
    From question and above equation,
                                 …(1)
    and                          …(2)
    Dividing equation (2) by (1),
    On solving we get, time taken to cool down from 62°C to 32°C, t = 8.6 minutes.


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