A) \[y={{x}^{2}}+constant\]
B) \[{{y}^{2}}=\text{ }{{x}^{2}}+constant\]
C) \[{{y}^{2}}=\,\,x+constant\]
D) \[xy\text{ }=\text{ }constant\]
Correct Answer: B
Solution :
| [b] \[\frac{dx}{dt}\,\,=\,\,y\] |
| \[\frac{dy}{dt}\,\,=\,\,x\] |
| \[\frac{dx}{dy}\,\,=\,\,\frac{y}{x}\] |
| \[xdx\text{ }=\text{ }ydy\] |
| \[{{y}^{2}}={{x}^{2}}+C\] |
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