A) \[\frac{1}{\sqrt{2}}m{{s}^{-2}}\]towards north-east
B) \[\frac{1}{2}m{{s}^{-2}}\]towards north
C) zero
D) \[\frac{1}{\sqrt{2}}m{{s}^{-2}}\]towards north-west
Correct Answer: D
Solution :
[d] Given, |
(unit vectors are assigned in accordance to directory given below) |
Change in velocity, |
Now, the average acceleration (in magnitude) |
For direction, |
Average acceleration is towards north-west. |
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