A) 1 : 16
B) 1 : 8
C) 1 : 2
D) 1 : 4
Correct Answer: A
Solution :
[a] |
Area covered \[=\text{ }\pi \,{{R}^{2}}\] |
When R is maximum area covered is also maximum |
\[R\,=\,\frac{{{u}^{2}}\,\sin \,2\,\theta }{g}\] |
\[{{R}_{\max }}\,=\,\frac{{{u}^{2}}\,}{g}\,(\theta \,\,=\,\,45{}^\circ )\] |
Area covered \[\propto {{u}^{4}}\] |
Ratio \[=\,{{\left( \frac{1}{2} \right)}^{4}}\,=\,\frac{1}{16}\] |
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